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web.xml의 param 가져오기

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by 까먹기전에 2015. 3. 5. 11:18

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protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

// TODO Auto-generated method stub

request.setCharacterEncoding("EUC-KR");

response.setContentType("text/html; charset=EUC-KR");

ServletContext application = this.getServletContext();

ServletConfig config = this.getServletConfig();

PrintWriter out=response.getWriter();

out.println( application.getInitParameter("xxx"));

out.println( config.getInitParameter("zzz") );






===========================web.xml==========================



  <servlet>

    <description></description>

    <display-name>Test</display-name>

    <servlet-name>Test</servlet-name>

    <servlet-class>a.b.Test</servlet-class>

    <init-param>

          <param-name>

             zzz

          </param-name>

          <param-value>

          yyy

          </param-value>

         </init-param>

  </servlet>

  <servlet-mapping>

    <servlet-name>Test</servlet-name>

    

    <url-pattern>/Test</url-pattern>

  </servlet-mapping>

  

    <context-param>

     <param-name>xxx</param-name>

     <param-value>www</param-value>

  </context-param>

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